Worked example
Mix 100 mL at 1 mol/L with 300 mL at 0.5 mol/L of the same solute. The total is 0.25 mol in an assumed 400 mL final volume, or 0.625 mol/L. At 58.44 g/mol, it contains 14.61 g solute.
Both solutions must contain the same solute
This is an inventory calculation for one chemical identity. Different solutes cannot be collapsed into one molarity. OpenStax defines molarity as moles of a solute per liter of solution; each starting amount follows concentration times volume.
Volumes are assumed additive
The displayed final volume is A volume plus B volume. Real mixtures may contract, expand, react or precipitate. If an accurate final volume is measured and differs from that sum, this simple estimate is not suitable.
Concentration is not a mixing instruction
The page does not evaluate compatibility, heat of mixing, purity or a preparation procedure. It only combines entered quantities. Zero molarity is valid for a solute-free solution; both volume inputs must still be positive.
Explore the related calculation
For a different starting point, try the molarity calculator or return to the main calculator. Browse the complete tool directory for this site.
Reference and corrections
The definitions and assumptions above follow these sources; the examples and calculator arithmetic are original to this page.
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